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(2^x)+(2^(-x))=17/4
We move all terms to the left:
(2^x)+(2^(-x))-(17/4)=0
We add all the numbers together, and all the variables
2^x+(2^(-1x))-(+17/4)=0
We get rid of parentheses
2^x+(2^(-1x))-17/4=0
We multiply all the terms by the denominator
2^x*4+((2^(-1x)))*4-17=0
Wy multiply elements
8x+((2^(-1x)))*4-17=0
We move all terms containing x to the left, all other terms to the right
8x+((2^(-1x)))*4=17
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